| #include "cache.h" | 
 | #include "tree.h" | 
 | #include "tree-walk.h" | 
 | #include "object-store.h" | 
 |  | 
 | static int score_missing(unsigned mode, const char *path) | 
 | { | 
 | 	int score; | 
 |  | 
 | 	if (S_ISDIR(mode)) | 
 | 		score = -1000; | 
 | 	else if (S_ISLNK(mode)) | 
 | 		score = -500; | 
 | 	else | 
 | 		score = -50; | 
 | 	return score; | 
 | } | 
 |  | 
 | static int score_differs(unsigned mode1, unsigned mode2, const char *path) | 
 | { | 
 | 	int score; | 
 |  | 
 | 	if (S_ISDIR(mode1) != S_ISDIR(mode2)) | 
 | 		score = -100; | 
 | 	else if (S_ISLNK(mode1) != S_ISLNK(mode2)) | 
 | 		score = -50; | 
 | 	else | 
 | 		score = -5; | 
 | 	return score; | 
 | } | 
 |  | 
 | static int score_matches(unsigned mode1, unsigned mode2, const char *path) | 
 | { | 
 | 	int score; | 
 |  | 
 | 	/* Heh, we found SHA-1 collisions between different kind of objects */ | 
 | 	if (S_ISDIR(mode1) != S_ISDIR(mode2)) | 
 | 		score = -100; | 
 | 	else if (S_ISLNK(mode1) != S_ISLNK(mode2)) | 
 | 		score = -50; | 
 |  | 
 | 	else if (S_ISDIR(mode1)) | 
 | 		score = 1000; | 
 | 	else if (S_ISLNK(mode1)) | 
 | 		score = 500; | 
 | 	else | 
 | 		score = 250; | 
 | 	return score; | 
 | } | 
 |  | 
 | static void *fill_tree_desc_strict(struct tree_desc *desc, | 
 | 				   const struct object_id *hash) | 
 | { | 
 | 	void *buffer; | 
 | 	enum object_type type; | 
 | 	unsigned long size; | 
 |  | 
 | 	buffer = read_object_file(hash, &type, &size); | 
 | 	if (!buffer) | 
 | 		die("unable to read tree (%s)", oid_to_hex(hash)); | 
 | 	if (type != OBJ_TREE) | 
 | 		die("%s is not a tree", oid_to_hex(hash)); | 
 | 	init_tree_desc(desc, buffer, size); | 
 | 	return buffer; | 
 | } | 
 |  | 
 | static int base_name_entries_compare(const struct name_entry *a, | 
 | 				     const struct name_entry *b) | 
 | { | 
 | 	return base_name_compare(a->path, tree_entry_len(a), a->mode, | 
 | 				 b->path, tree_entry_len(b), b->mode); | 
 | } | 
 |  | 
 | /* | 
 |  * Inspect two trees, and give a score that tells how similar they are. | 
 |  */ | 
 | static int score_trees(const struct object_id *hash1, const struct object_id *hash2) | 
 | { | 
 | 	struct tree_desc one; | 
 | 	struct tree_desc two; | 
 | 	void *one_buf = fill_tree_desc_strict(&one, hash1); | 
 | 	void *two_buf = fill_tree_desc_strict(&two, hash2); | 
 | 	int score = 0; | 
 |  | 
 | 	for (;;) { | 
 | 		int cmp; | 
 |  | 
 | 		if (one.size && two.size) | 
 | 			cmp = base_name_entries_compare(&one.entry, &two.entry); | 
 | 		else if (one.size) | 
 | 			/* two lacks this entry */ | 
 | 			cmp = -1; | 
 | 		else if (two.size) | 
 | 			/* two has more entries */ | 
 | 			cmp = 1; | 
 | 		else | 
 | 			break; | 
 |  | 
 | 		if (cmp < 0) { | 
 | 			/* path1 does not appear in two */ | 
 | 			score += score_missing(one.entry.mode, one.entry.path); | 
 | 			update_tree_entry(&one); | 
 | 		} else if (cmp > 0) { | 
 | 			/* path2 does not appear in one */ | 
 | 			score += score_missing(two.entry.mode, two.entry.path); | 
 | 			update_tree_entry(&two); | 
 | 		} else { | 
 | 			/* path appears in both */ | 
 | 			if (!oideq(one.entry.oid, two.entry.oid)) { | 
 | 				/* they are different */ | 
 | 				score += score_differs(one.entry.mode, | 
 | 						       two.entry.mode, | 
 | 						       one.entry.path); | 
 | 			} else { | 
 | 				/* same subtree or blob */ | 
 | 				score += score_matches(one.entry.mode, | 
 | 						       two.entry.mode, | 
 | 						       one.entry.path); | 
 | 			} | 
 | 			update_tree_entry(&one); | 
 | 			update_tree_entry(&two); | 
 | 		} | 
 | 	} | 
 | 	free(one_buf); | 
 | 	free(two_buf); | 
 | 	return score; | 
 | } | 
 |  | 
 | /* | 
 |  * Match one itself and its subtrees with two and pick the best match. | 
 |  */ | 
 | static void match_trees(const struct object_id *hash1, | 
 | 			const struct object_id *hash2, | 
 | 			int *best_score, | 
 | 			char **best_match, | 
 | 			const char *base, | 
 | 			int recurse_limit) | 
 | { | 
 | 	struct tree_desc one; | 
 | 	void *one_buf = fill_tree_desc_strict(&one, hash1); | 
 |  | 
 | 	while (one.size) { | 
 | 		const char *path; | 
 | 		const struct object_id *elem; | 
 | 		unsigned mode; | 
 | 		int score; | 
 |  | 
 | 		elem = tree_entry_extract(&one, &path, &mode); | 
 | 		if (!S_ISDIR(mode)) | 
 | 			goto next; | 
 | 		score = score_trees(elem, hash2); | 
 | 		if (*best_score < score) { | 
 | 			free(*best_match); | 
 | 			*best_match = xstrfmt("%s%s", base, path); | 
 | 			*best_score = score; | 
 | 		} | 
 | 		if (recurse_limit) { | 
 | 			char *newbase = xstrfmt("%s%s/", base, path); | 
 | 			match_trees(elem, hash2, best_score, best_match, | 
 | 				    newbase, recurse_limit - 1); | 
 | 			free(newbase); | 
 | 		} | 
 |  | 
 | 	next: | 
 | 		update_tree_entry(&one); | 
 | 	} | 
 | 	free(one_buf); | 
 | } | 
 |  | 
 | /* | 
 |  * A tree "oid1" has a subdirectory at "prefix".  Come up with a tree object by | 
 |  * replacing it with another tree "oid2". | 
 |  */ | 
 | static int splice_tree(const struct object_id *oid1, const char *prefix, | 
 | 		       const struct object_id *oid2, struct object_id *result) | 
 | { | 
 | 	char *subpath; | 
 | 	int toplen; | 
 | 	char *buf; | 
 | 	unsigned long sz; | 
 | 	struct tree_desc desc; | 
 | 	struct object_id *rewrite_here; | 
 | 	const struct object_id *rewrite_with; | 
 | 	struct object_id subtree; | 
 | 	enum object_type type; | 
 | 	int status; | 
 |  | 
 | 	subpath = strchrnul(prefix, '/'); | 
 | 	toplen = subpath - prefix; | 
 | 	if (*subpath) | 
 | 		subpath++; | 
 |  | 
 | 	buf = read_object_file(oid1, &type, &sz); | 
 | 	if (!buf) | 
 | 		die("cannot read tree %s", oid_to_hex(oid1)); | 
 | 	init_tree_desc(&desc, buf, sz); | 
 |  | 
 | 	rewrite_here = NULL; | 
 | 	while (desc.size) { | 
 | 		const char *name; | 
 | 		unsigned mode; | 
 | 		const struct object_id *oid; | 
 |  | 
 | 		oid = tree_entry_extract(&desc, &name, &mode); | 
 | 		if (strlen(name) == toplen && | 
 | 		    !memcmp(name, prefix, toplen)) { | 
 | 			if (!S_ISDIR(mode)) | 
 | 				die("entry %s in tree %s is not a tree", name, | 
 | 				    oid_to_hex(oid1)); | 
 | 			rewrite_here = (struct object_id *)oid; | 
 | 			break; | 
 | 		} | 
 | 		update_tree_entry(&desc); | 
 | 	} | 
 | 	if (!rewrite_here) | 
 | 		die("entry %.*s not found in tree %s", toplen, prefix, | 
 | 		    oid_to_hex(oid1)); | 
 | 	if (*subpath) { | 
 | 		status = splice_tree(rewrite_here, subpath, oid2, &subtree); | 
 | 		if (status) | 
 | 			return status; | 
 | 		rewrite_with = &subtree; | 
 | 	} else { | 
 | 		rewrite_with = oid2; | 
 | 	} | 
 | 	oidcpy(rewrite_here, rewrite_with); | 
 | 	status = write_object_file(buf, sz, tree_type, result); | 
 | 	free(buf); | 
 | 	return status; | 
 | } | 
 |  | 
 | /* | 
 |  * We are trying to come up with a merge between one and two that | 
 |  * results in a tree shape similar to one.  The tree two might | 
 |  * correspond to a subtree of one, in which case it needs to be | 
 |  * shifted down by prefixing otherwise empty directories.  On the | 
 |  * other hand, it could cover tree one and we might need to pick a | 
 |  * subtree of it. | 
 |  */ | 
 | void shift_tree(const struct object_id *hash1, | 
 | 		const struct object_id *hash2, | 
 | 		struct object_id *shifted, | 
 | 		int depth_limit) | 
 | { | 
 | 	char *add_prefix; | 
 | 	char *del_prefix; | 
 | 	int add_score, del_score; | 
 |  | 
 | 	/* | 
 | 	 * NEEDSWORK: this limits the recursion depth to hardcoded | 
 | 	 * value '2' to avoid excessive overhead. | 
 | 	 */ | 
 | 	if (!depth_limit) | 
 | 		depth_limit = 2; | 
 |  | 
 | 	add_score = del_score = score_trees(hash1, hash2); | 
 | 	add_prefix = xcalloc(1, 1); | 
 | 	del_prefix = xcalloc(1, 1); | 
 |  | 
 | 	/* | 
 | 	 * See if one's subtree resembles two; if so we need to prefix | 
 | 	 * two with a few fake trees to match the prefix. | 
 | 	 */ | 
 | 	match_trees(hash1, hash2, &add_score, &add_prefix, "", depth_limit); | 
 |  | 
 | 	/* | 
 | 	 * See if two's subtree resembles one; if so we need to | 
 | 	 * pick only subtree of two. | 
 | 	 */ | 
 | 	match_trees(hash2, hash1, &del_score, &del_prefix, "", depth_limit); | 
 |  | 
 | 	/* Assume we do not have to do any shifting */ | 
 | 	oidcpy(shifted, hash2); | 
 |  | 
 | 	if (add_score < del_score) { | 
 | 		/* We need to pick a subtree of two */ | 
 | 		unsigned mode; | 
 |  | 
 | 		if (!*del_prefix) | 
 | 			return; | 
 |  | 
 | 		if (get_tree_entry(hash2, del_prefix, shifted, &mode)) | 
 | 			die("cannot find path %s in tree %s", | 
 | 			    del_prefix, oid_to_hex(hash2)); | 
 | 		return; | 
 | 	} | 
 |  | 
 | 	if (!*add_prefix) | 
 | 		return; | 
 |  | 
 | 	splice_tree(hash1, add_prefix, hash2, shifted); | 
 | } | 
 |  | 
 | /* | 
 |  * The user says the trees will be shifted by this much. | 
 |  * Unfortunately we cannot fundamentally tell which one to | 
 |  * be prefixed, as recursive merge can work in either direction. | 
 |  */ | 
 | void shift_tree_by(const struct object_id *hash1, | 
 | 		   const struct object_id *hash2, | 
 | 		   struct object_id *shifted, | 
 | 		   const char *shift_prefix) | 
 | { | 
 | 	struct object_id sub1, sub2; | 
 | 	unsigned mode1, mode2; | 
 | 	unsigned candidate = 0; | 
 |  | 
 | 	/* Can hash2 be a tree at shift_prefix in tree hash1? */ | 
 | 	if (!get_tree_entry(hash1, shift_prefix, &sub1, &mode1) && | 
 | 	    S_ISDIR(mode1)) | 
 | 		candidate |= 1; | 
 |  | 
 | 	/* Can hash1 be a tree at shift_prefix in tree hash2? */ | 
 | 	if (!get_tree_entry(hash2, shift_prefix, &sub2, &mode2) && | 
 | 	    S_ISDIR(mode2)) | 
 | 		candidate |= 2; | 
 |  | 
 | 	if (candidate == 3) { | 
 | 		/* Both are plausible -- we need to evaluate the score */ | 
 | 		int best_score = score_trees(hash1, hash2); | 
 | 		int score; | 
 |  | 
 | 		candidate = 0; | 
 | 		score = score_trees(&sub1, hash2); | 
 | 		if (score > best_score) { | 
 | 			candidate = 1; | 
 | 			best_score = score; | 
 | 		} | 
 | 		score = score_trees(&sub2, hash1); | 
 | 		if (score > best_score) | 
 | 			candidate = 2; | 
 | 	} | 
 |  | 
 | 	if (!candidate) { | 
 | 		/* Neither is plausible -- do not shift */ | 
 | 		oidcpy(shifted, hash2); | 
 | 		return; | 
 | 	} | 
 |  | 
 | 	if (candidate == 1) | 
 | 		/* | 
 | 		 * shift tree2 down by adding shift_prefix above it | 
 | 		 * to match tree1. | 
 | 		 */ | 
 | 		splice_tree(hash1, shift_prefix, hash2, shifted); | 
 | 	else | 
 | 		/* | 
 | 		 * shift tree2 up by removing shift_prefix from it | 
 | 		 * to match tree1. | 
 | 		 */ | 
 | 		oidcpy(shifted, &sub2); | 
 | } |