|  | #include "cache.h" | 
|  | #include "tree.h" | 
|  | #include "tree-walk.h" | 
|  |  | 
|  | static int score_missing(unsigned mode, const char *path) | 
|  | { | 
|  | int score; | 
|  |  | 
|  | if (S_ISDIR(mode)) | 
|  | score = -1000; | 
|  | else if (S_ISLNK(mode)) | 
|  | score = -500; | 
|  | else | 
|  | score = -50; | 
|  | return score; | 
|  | } | 
|  |  | 
|  | static int score_differs(unsigned mode1, unsigned mode2, const char *path) | 
|  | { | 
|  | int score; | 
|  |  | 
|  | if (S_ISDIR(mode1) != S_ISDIR(mode2)) | 
|  | score = -100; | 
|  | else if (S_ISLNK(mode1) != S_ISLNK(mode2)) | 
|  | score = -50; | 
|  | else | 
|  | score = -5; | 
|  | return score; | 
|  | } | 
|  |  | 
|  | static int score_matches(unsigned mode1, unsigned mode2, const char *path) | 
|  | { | 
|  | int score; | 
|  |  | 
|  | /* Heh, we found SHA-1 collisions between different kind of objects */ | 
|  | if (S_ISDIR(mode1) != S_ISDIR(mode2)) | 
|  | score = -100; | 
|  | else if (S_ISLNK(mode1) != S_ISLNK(mode2)) | 
|  | score = -50; | 
|  |  | 
|  | else if (S_ISDIR(mode1)) | 
|  | score = 1000; | 
|  | else if (S_ISLNK(mode1)) | 
|  | score = 500; | 
|  | else | 
|  | score = 250; | 
|  | return score; | 
|  | } | 
|  |  | 
|  | static void *fill_tree_desc_strict(struct tree_desc *desc, | 
|  | const unsigned char *hash) | 
|  | { | 
|  | void *buffer; | 
|  | enum object_type type; | 
|  | unsigned long size; | 
|  |  | 
|  | buffer = read_sha1_file(hash, &type, &size); | 
|  | if (!buffer) | 
|  | die("unable to read tree (%s)", sha1_to_hex(hash)); | 
|  | if (type != OBJ_TREE) | 
|  | die("%s is not a tree", sha1_to_hex(hash)); | 
|  | init_tree_desc(desc, buffer, size); | 
|  | return buffer; | 
|  | } | 
|  |  | 
|  | static int base_name_entries_compare(const struct name_entry *a, | 
|  | const struct name_entry *b) | 
|  | { | 
|  | return base_name_compare(a->path, tree_entry_len(a), a->mode, | 
|  | b->path, tree_entry_len(b), b->mode); | 
|  | } | 
|  |  | 
|  | /* | 
|  | * Inspect two trees, and give a score that tells how similar they are. | 
|  | */ | 
|  | static int score_trees(const unsigned char *hash1, const unsigned char *hash2) | 
|  | { | 
|  | struct tree_desc one; | 
|  | struct tree_desc two; | 
|  | void *one_buf = fill_tree_desc_strict(&one, hash1); | 
|  | void *two_buf = fill_tree_desc_strict(&two, hash2); | 
|  | int score = 0; | 
|  |  | 
|  | for (;;) { | 
|  | struct name_entry e1, e2; | 
|  | int got_entry_from_one = tree_entry(&one, &e1); | 
|  | int got_entry_from_two = tree_entry(&two, &e2); | 
|  | int cmp; | 
|  |  | 
|  | if (got_entry_from_one && got_entry_from_two) | 
|  | cmp = base_name_entries_compare(&e1, &e2); | 
|  | else if (got_entry_from_one) | 
|  | /* two lacks this entry */ | 
|  | cmp = -1; | 
|  | else if (got_entry_from_two) | 
|  | /* two has more entries */ | 
|  | cmp = 1; | 
|  | else | 
|  | break; | 
|  |  | 
|  | if (cmp < 0) | 
|  | /* path1 does not appear in two */ | 
|  | score += score_missing(e1.mode, e1.path); | 
|  | else if (cmp > 0) | 
|  | /* path2 does not appear in one */ | 
|  | score += score_missing(e2.mode, e2.path); | 
|  | else if (hashcmp(e1.sha1, e2.sha1)) | 
|  | /* they are different */ | 
|  | score += score_differs(e1.mode, e2.mode, e1.path); | 
|  | else | 
|  | /* same subtree or blob */ | 
|  | score += score_matches(e1.mode, e2.mode, e1.path); | 
|  | } | 
|  | free(one_buf); | 
|  | free(two_buf); | 
|  | return score; | 
|  | } | 
|  |  | 
|  | /* | 
|  | * Match one itself and its subtrees with two and pick the best match. | 
|  | */ | 
|  | static void match_trees(const unsigned char *hash1, | 
|  | const unsigned char *hash2, | 
|  | int *best_score, | 
|  | char **best_match, | 
|  | const char *base, | 
|  | int recurse_limit) | 
|  | { | 
|  | struct tree_desc one; | 
|  | void *one_buf = fill_tree_desc_strict(&one, hash1); | 
|  |  | 
|  | while (one.size) { | 
|  | const char *path; | 
|  | const unsigned char *elem; | 
|  | unsigned mode; | 
|  | int score; | 
|  |  | 
|  | elem = tree_entry_extract(&one, &path, &mode); | 
|  | if (!S_ISDIR(mode)) | 
|  | goto next; | 
|  | score = score_trees(elem, hash2); | 
|  | if (*best_score < score) { | 
|  | free(*best_match); | 
|  | *best_match = xstrfmt("%s%s", base, path); | 
|  | *best_score = score; | 
|  | } | 
|  | if (recurse_limit) { | 
|  | char *newbase = xstrfmt("%s%s/", base, path); | 
|  | match_trees(elem, hash2, best_score, best_match, | 
|  | newbase, recurse_limit - 1); | 
|  | free(newbase); | 
|  | } | 
|  |  | 
|  | next: | 
|  | update_tree_entry(&one); | 
|  | } | 
|  | free(one_buf); | 
|  | } | 
|  |  | 
|  | /* | 
|  | * A tree "hash1" has a subdirectory at "prefix".  Come up with a | 
|  | * tree object by replacing it with another tree "hash2". | 
|  | */ | 
|  | static int splice_tree(const unsigned char *hash1, | 
|  | const char *prefix, | 
|  | const unsigned char *hash2, | 
|  | unsigned char *result) | 
|  | { | 
|  | char *subpath; | 
|  | int toplen; | 
|  | char *buf; | 
|  | unsigned long sz; | 
|  | struct tree_desc desc; | 
|  | unsigned char *rewrite_here; | 
|  | const unsigned char *rewrite_with; | 
|  | unsigned char subtree[20]; | 
|  | enum object_type type; | 
|  | int status; | 
|  |  | 
|  | subpath = strchrnul(prefix, '/'); | 
|  | toplen = subpath - prefix; | 
|  | if (*subpath) | 
|  | subpath++; | 
|  |  | 
|  | buf = read_sha1_file(hash1, &type, &sz); | 
|  | if (!buf) | 
|  | die("cannot read tree %s", sha1_to_hex(hash1)); | 
|  | init_tree_desc(&desc, buf, sz); | 
|  |  | 
|  | rewrite_here = NULL; | 
|  | while (desc.size) { | 
|  | const char *name; | 
|  | unsigned mode; | 
|  | const unsigned char *sha1; | 
|  |  | 
|  | sha1 = tree_entry_extract(&desc, &name, &mode); | 
|  | if (strlen(name) == toplen && | 
|  | !memcmp(name, prefix, toplen)) { | 
|  | if (!S_ISDIR(mode)) | 
|  | die("entry %s in tree %s is not a tree", | 
|  | name, sha1_to_hex(hash1)); | 
|  | rewrite_here = (unsigned char *) sha1; | 
|  | break; | 
|  | } | 
|  | update_tree_entry(&desc); | 
|  | } | 
|  | if (!rewrite_here) | 
|  | die("entry %.*s not found in tree %s", | 
|  | toplen, prefix, sha1_to_hex(hash1)); | 
|  | if (*subpath) { | 
|  | status = splice_tree(rewrite_here, subpath, hash2, subtree); | 
|  | if (status) | 
|  | return status; | 
|  | rewrite_with = subtree; | 
|  | } | 
|  | else | 
|  | rewrite_with = hash2; | 
|  | hashcpy(rewrite_here, rewrite_with); | 
|  | status = write_sha1_file(buf, sz, tree_type, result); | 
|  | free(buf); | 
|  | return status; | 
|  | } | 
|  |  | 
|  | /* | 
|  | * We are trying to come up with a merge between one and two that | 
|  | * results in a tree shape similar to one.  The tree two might | 
|  | * correspond to a subtree of one, in which case it needs to be | 
|  | * shifted down by prefixing otherwise empty directories.  On the | 
|  | * other hand, it could cover tree one and we might need to pick a | 
|  | * subtree of it. | 
|  | */ | 
|  | void shift_tree(const unsigned char *hash1, | 
|  | const unsigned char *hash2, | 
|  | unsigned char *shifted, | 
|  | int depth_limit) | 
|  | { | 
|  | char *add_prefix; | 
|  | char *del_prefix; | 
|  | int add_score, del_score; | 
|  |  | 
|  | /* | 
|  | * NEEDSWORK: this limits the recursion depth to hardcoded | 
|  | * value '2' to avoid excessive overhead. | 
|  | */ | 
|  | if (!depth_limit) | 
|  | depth_limit = 2; | 
|  |  | 
|  | add_score = del_score = score_trees(hash1, hash2); | 
|  | add_prefix = xcalloc(1, 1); | 
|  | del_prefix = xcalloc(1, 1); | 
|  |  | 
|  | /* | 
|  | * See if one's subtree resembles two; if so we need to prefix | 
|  | * two with a few fake trees to match the prefix. | 
|  | */ | 
|  | match_trees(hash1, hash2, &add_score, &add_prefix, "", depth_limit); | 
|  |  | 
|  | /* | 
|  | * See if two's subtree resembles one; if so we need to | 
|  | * pick only subtree of two. | 
|  | */ | 
|  | match_trees(hash2, hash1, &del_score, &del_prefix, "", depth_limit); | 
|  |  | 
|  | /* Assume we do not have to do any shifting */ | 
|  | hashcpy(shifted, hash2); | 
|  |  | 
|  | if (add_score < del_score) { | 
|  | /* We need to pick a subtree of two */ | 
|  | unsigned mode; | 
|  |  | 
|  | if (!*del_prefix) | 
|  | return; | 
|  |  | 
|  | if (get_tree_entry(hash2, del_prefix, shifted, &mode)) | 
|  | die("cannot find path %s in tree %s", | 
|  | del_prefix, sha1_to_hex(hash2)); | 
|  | return; | 
|  | } | 
|  |  | 
|  | if (!*add_prefix) | 
|  | return; | 
|  |  | 
|  | splice_tree(hash1, add_prefix, hash2, shifted); | 
|  | } | 
|  |  | 
|  | /* | 
|  | * The user says the trees will be shifted by this much. | 
|  | * Unfortunately we cannot fundamentally tell which one to | 
|  | * be prefixed, as recursive merge can work in either direction. | 
|  | */ | 
|  | void shift_tree_by(const unsigned char *hash1, | 
|  | const unsigned char *hash2, | 
|  | unsigned char *shifted, | 
|  | const char *shift_prefix) | 
|  | { | 
|  | unsigned char sub1[20], sub2[20]; | 
|  | unsigned mode1, mode2; | 
|  | unsigned candidate = 0; | 
|  |  | 
|  | /* Can hash2 be a tree at shift_prefix in tree hash1? */ | 
|  | if (!get_tree_entry(hash1, shift_prefix, sub1, &mode1) && | 
|  | S_ISDIR(mode1)) | 
|  | candidate |= 1; | 
|  |  | 
|  | /* Can hash1 be a tree at shift_prefix in tree hash2? */ | 
|  | if (!get_tree_entry(hash2, shift_prefix, sub2, &mode2) && | 
|  | S_ISDIR(mode2)) | 
|  | candidate |= 2; | 
|  |  | 
|  | if (candidate == 3) { | 
|  | /* Both are plausible -- we need to evaluate the score */ | 
|  | int best_score = score_trees(hash1, hash2); | 
|  | int score; | 
|  |  | 
|  | candidate = 0; | 
|  | score = score_trees(sub1, hash2); | 
|  | if (score > best_score) { | 
|  | candidate = 1; | 
|  | best_score = score; | 
|  | } | 
|  | score = score_trees(sub2, hash1); | 
|  | if (score > best_score) | 
|  | candidate = 2; | 
|  | } | 
|  |  | 
|  | if (!candidate) { | 
|  | /* Neither is plausible -- do not shift */ | 
|  | hashcpy(shifted, hash2); | 
|  | return; | 
|  | } | 
|  |  | 
|  | if (candidate == 1) | 
|  | /* | 
|  | * shift tree2 down by adding shift_prefix above it | 
|  | * to match tree1. | 
|  | */ | 
|  | splice_tree(hash1, shift_prefix, hash2, shifted); | 
|  | else | 
|  | /* | 
|  | * shift tree2 up by removing shift_prefix from it | 
|  | * to match tree1. | 
|  | */ | 
|  | hashcpy(shifted, sub2); | 
|  | } |